After studying the impact of the number of projections [Link], it is time to explore the ins and outs of the angular coverage and its consequences on the quality of the reconstructed image.
2- Which angular coverage ?
2-1- Why not from 0 to 360°?
In the previous posts, sinograms were calculated from 0 to 180°, why? ... simply because projections calculated at an angle of α and of (α + 180°) are identical and thus are redundant for the reconstruction.
Explanation: If we choose two projections respectively calculated at 30° and 210° (=30°+180°) from the Lena image (Fig.1).
Fig.1: Lena respectively rotated by 30° and 210° (=30+180°) |
Now, when we compute the back-projection. The first projection is back-projected and rotated by 30° leading to image of Fig.3A. The second back-projection of 210° yields ... the same exact pattern (Fig. 3B).
Fig.3: Comparison between 30° and 210° back-projections. |
Note: Keep in mind that in Fourier Space, a (back-) projection corresponds to a 1D-central slice. Thus, to cover the whole 2D-Fourier space, we only need an angular range of 0° to 180° as shown in the following scheme.This confirms that these extra data (180° to 360° projections) are redundant and are just slowing down the reconstruction process without any improvement. In conclusion, we only need a maximum angular coverage of 180°.
Fig. 3bis: Scheme of the 2D-Fourier space filled by the 0° to 180° projections. There is no need to more than 180° to fully cover the space.
Note: Depending of the experimental device used for the data collection, it's sometimes interesting to collect over several turns as explained in this post [Link].2-2- Is it possible to reduce the angular coverage?
W O R K I N P R O G R E S S
Example calculated from 30° to 150°
Note: In electron microscopy, due to mechanical constraints, the data collection is usually done between -55° to +55° yielding in 3D the so-called missing wedge.
No comments:
Post a Comment